Derivative of sec(x) - Proof and Explanation

To find the derivative of sec(x), we start by rewriting it in a form that might be easier to differentiate. Recall that:

sec(x)=1cos(x)

To differentiate this, we use the <strong>quotient rule</strong>. The quotient rule states that for two functions u(x) and v(x), the derivative of their quotient uv is given by:

ddx(uv)=vdudxudvdxv2

In our case:

Step 1: Differentiate u and v

  1. The derivative of u with respect to x is 0 because u=1 – a constant.
  2. The derivative of v=cos(x) with respect to x is sin(x).

Step 2: Apply the quotient rule

Plugging these into the quotient rule:

ddx(1cos(x))=cos(x)·01·(sin(x))cos2(x)

This simplifies to:

sin(x)cos2(x)

Step 3: Simplify the result

Now, we can rewrite this expression in terms of other trigonometric functions:

sin(x)cos2(x)=sin(x)cos(x)·1cos(x)=tan(x)·sec(x)

Thus, the derivative of sec(x) is:

sec(x)·tan(x)

Q.E.D.